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NCERT Solutions for Class 11 Chemistry Chapter 9 Hydrocarbons

NCERT Solutions for Class 11 Chemistry Chapter 9 Hydrocarbons provides comprehensive coverage of aliphatic hydrocarbons (alkanes, alkenes, alkynes) and aromatic hydrocarbons (benzene). Key topics include IUPAC nomenclature, physical properties, conformational analysis of ethane, addition mechanisms (Markovnikov & Anti-Markovnikov rules), acidic nature of alkynes, aromaticity (Hückel's Rule), electrophilic substitution reactions in benzene, directive influences of functional groups, and environmental impacts of polynuclear hydrocarbons.

Overview of Topics & Subtopics (Click to Jump)

1. Alkanes: Structure, Nomenclature, Preparation, Reactions & Conformations

Short Note:

• Saturated Hydrocarbons (CnH2n+2): Carbon atoms are sp3 hybridized forming single C-C and C-H sigma bonds.

• Methods of Preparation:

  - From Alkyl Halides: Wurtz Reaction: 2R-X + 2Na (dry ether) → R-R + 2NaX.

  - Decarboxylation: R-COONa + NaOH (CaO, heat) → R-H + Na2CO3.

  - Kolbe's Electrolytic Method: 2R-COOK + 2H2O (electrolysis) → R-R + 2CO2 + H2 + 2KOH.

• Conformations of Ethane: Infinite spatial arrangements due to free rotation around C-C single bond.

  - Eclipsed Conformation: Hydrogen atoms on both carbons are directly behind each other (Maximum torsional strain, least stable).

  - Staggered Conformation: Hydrogen atoms are as far apart as possible (Minimum torsional strain, most stable by 12.5 kJ/mol).

2. Alkenes & Alkynes: Preparation, Addition Reactions & Ozonolysis

Short Note:

• Alkenes (CnH2n): Contain at least one C=C double bond (sp2 hybridized carbon). Exhibit Geometrical Isomerism (cis/trans) due to restricted rotation about C=C.

• Electrophilic Addition Reactions:

  - Markovnikov's Rule: When an unsymmetrical reagent (e.g., HBr) adds to an unsymmetrical alkene, the negative part adds to the carbon with fewer hydrogen atoms.

  - Peroxide Effect (Kharasch Effect): Addition of HBr in the presence of organic peroxide follows Anti-Markovnikov's Rule via a free radical mechanism.

  - Ozonolysis: Cleavage of C=C by ozone (O3 followed by Zn/H2O) to form aldehydes and/or ketones (used to locate double bond positions).

• Alkynes (CnH2n-2): Contain C≡C triple bond (sp hybridized carbon). Terminal alkynes are acidic in nature due to high s-character (50%) of sp hybridized carbon (e.g., react with Na or NaNH2 to release H2 gas).

3. Aromatic Hydrocarbons: Benzene, Aromaticity & Electrophilic Substitution

Short Note:

• Aromaticity (Hückel's Rule): A compound is aromatic if it is cyclic, planar, completely conjugated, and possesses (4n + 2) π electrons (where n = 0, 1, 2, 3...).

• Structure of Benzene: Planar ring of 6 sp2 hybridized carbon atoms with a delocalized π-electron cloud above and below the ring plane.

• Electrophilic Aromatic Substitution (SE) Mechanisms:

  - Nitration: Benzene + Conc. HNO3 + Conc. H2SO4 → Nitrobenzene + H2O (Electrophile: NO2+).

  - Halogenation: Benzene + Cl2 (Anhydrous FeCl3) → Chlorobenzene + HCl (Electrophile: Cl+).

  - Sulfonation: Benzene + Fuming H2SO4 (SO3) → Benzenesulfonic acid (Electrophile: SO3).

  - Friedel-Crafts Alkylation: Benzene + CH3Cl (Anhydrous AlCl3) → Toluene + HCl (Electrophile: CH3+).

  - Friedel-Crafts Acylation: Benzene + CH3COCl (Anhydrous AlCl3) → Acetophenone + HCl (Electrophile: CH3C+=O).

4. Directive Influence of Groups, Carcinogenicity & Toxicity

Short Note:

• Directive Influence in Monosubstituted Benzene:

  - Ortho and Para Directors (Activating Groups): Groups that increase electron density at ortho/para positions through +R/+I effects (e.g., -OH, -NH2, -OCH3, -CH3). Halogens (-X) are ortho/para directing due to +R, but deactivating due to strong -I effect.

  - Meta Directors (Deactivating Groups): Electron-withdrawing groups that decrease electron density overall, especially at ortho/para positions through -R/-I effects, directing coming electrophiles to meta position (e.g., -NO2, -COOH, -CHO, -CN, -SO3H).

• Carcinogenicity & Toxicity: Polynuclear aromatic hydrocarbons containing more than two fused benzene rings (e.g., 1,2-benzanthracene, 3,4-benzopyrene) are toxic and carcinogenic. Formed during incomplete combustion of organic materials (coal, tobacco, petroleum).

Intext & Conceptual Questions

Q1: Predict the major product formed when propene (CH3-CH=CH2) reacts with HBr in: (a) absence of peroxide, (b) presence of peroxide. Explain the rules applied.
Answer:
(a) In the absence of peroxide:
Reaction follows Markovnikov's Rule. The hydrogen ion (H+) adds to C-3 to form the more stable secondary carbocation (CH3-CH+-CH3).
• Major Product: 2-Bromopropane (CH3-CH(Br)-CH3).

(b) In the presence of organic peroxide:
Reaction follows Anti-Markovnikov's Rule (Peroxide / Kharasch Effect) via a free radical mechanism. Bromine radical (Br•) adds to C-3 to yield the more stable secondary free radical.
• Major Product: 1-Bromopropane (CH3-CH2-CH2Br).

Textbook Chapter End Exercise Questions

Q1: What are the necessary conditions for a compound to be aromatic according to Hückel's Rule? State whether Cyclooctatetraene is aromatic or non-aromatic.
Answer:
Conditions for Aromaticity (Hückel's Rule):
1. The molecule must be cyclic.
2. The molecule must be planar (all carbon atoms in the ring must be sp2 hybridized).
3. There must be complete delocalization of π-electrons throughout the ring.
4. The ring must contain (4n + 2) π electrons, where n is a non-negative integer (n = 0, 1, 2, 3...).

Analysis of Cyclooctatetraene (C8H8):
• Cyclooctatetraene contains 4 double bonds, meaning it has 8 π electrons.
• Setting 4n + 2 = 8 gives 4n = 6 ⇒ n = 1.5 (not an integer).
• Additionally, cyclooctatetraene adopts a non-planar tub-shaped structure to avoid anti-aromatic instability.

Conclusion: Cyclooctatetraene is non-aromatic.
Q2: Draw the Sawhorse and Newman projections for the staggered and eclipsed conformations of ethane. Explain why the staggered conformation is more stable.
Answer:
Conformations of Ethane (C2H6):

• Sawhorse Projections:
- Eclipsed: C-H bonds on both carbon atoms are parallel and aligned in the same plane.
- Staggered: C-H bonds on the rear carbon are rotated by 60° relative to those on the front carbon.

• Newman Projections:
- Eclipsed: Hydrogen atoms on the rear carbon (represented by the outer circle) are directly hidden behind hydrogen atoms on the front carbon (represented by the central vertex).
- Staggered: Hydrogen atoms are evenly spaced at 60° dihedral angles (dihedral angle = 60°).

Reason for Higher Stability of Staggered Conformation:
1. Minimum Torsional Strain: In the staggered conformation, electron clouds of C-H sigma bonds are as far apart as possible, leading to minimum electrostatic repulsion.
2. In contrast, in the eclipsed conformation, electron pairs of C-H bonds are directly facing each other, creating strong repulsive interactions (torsional strain of ~12.5 kJ/mol).

Therefore, the staggered conformation possesses lower potential energy and is more stable than the eclipsed conformation.
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Class 11 › Chemistry › Hydrocarbons
Chapter notesRead the chapterPractice MCQsCheck what you rememberChapter test10 questions on one pageOnline testTest 1, 2 and 3, one question at a timePYQPrevious year questionsStudy materialPDF notes
Topics in this chapter: Alkanes: Structure, Nomenclature, Preparation, Reactions & ConformationsAlkenes & Alkynes: Preparation, Geometrical Isomerism, Addition Reactions & OzonolysisAromatic Hydrocarbons: Benzene, Aromaticity (Hückel's Rule) & Electrophilic SubstitutionDirective Influence of Groups, Carcinogenicity & Toxicity